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Rotating a Parabola
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The Square of a Binomial
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Multiplying Binomials Using the FOIL Method
Imaginary Numbers
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Solving Quadratic Equations
Algebra
Order of Operations
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The Appearance of a Polynomial Equation
Standard Form of a Line
Positive Integral Divisors
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Solving Linear Systems of Equations by Elimination
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Use of Parentheses or Brackets (The Distributive Law)
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Multiplying Decimals
Use of Parentheses or Brackets (The Distributive Law)
Simplifying Complex Fractions 1
Adding Fractions
Simplifying Complex Fractions
Solutions to Linear Equations in Two Variables
Quadratic Expressions Completing Squares
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Rise and Run
Graphing Exponential Functions
Multiplying by a Monomial
The Cartesian Coordinate System
Writing the Terms of a Polynomial in Descending Order
Fractions
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Powers of ten (Scientific Notation)
Comparing Integers on a Number Line
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Factoring Out the Greatest Common Factor
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Properties of Exponents
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The Quadratic Formula
Writing a Quadratic with Given Solutions
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Combining Like Radical Terms
Solving Systems of Equations Using Substitution
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Product of a Sum and a Difference
Solving First Degree Inequalities
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Standard Form of a Line

If x students paid $5 each and y adults paid $7 each to attend a play for which the ticket sales totaled $1900, then we can write the equation 5x + 7y = 1900. This form of a linear equation is common in applications. It is called standard form.

 

Standard Form

The equation of a line in standard form is Ax + By = C, where A, B, and C are real numbers with A and B not both zero.

 

The numbers A, B, and C in standard form can be any real numbers, but it is a common practice to write standard form using only integers and a positive coefficient for x.

 

Example 1

Changing to standard form

Write the equation in standard form using only integers and a positive coefficient for x.

Solution

Use the properties of equality to get the equation in the form Ax + By = C:

y Original equation
Subtract from each side.
Multiply each side by 4 to get integral coefficients.
-2x + 4y = -3 Distributive property
2x - 4y = 3 Multiply by -1 to make the coefficient of x positive.

To find the slope and y-intercept of a line written in standard form, we convert the equation to slope-intercept form.

 

Example 2

Changing to slope-intercept form

Find the slope and y-intercept of the line 3x - 2y = 5.

Solution

Solve for y to get slope-intercept form:

3x - 2y = 5 Original equation
-2y = -3x + 5 Subtract 3x from each side.
y Divide each side by -2.

The slope is , and the y-intercept is .

 

Helpful Hint

Solve Ax + By = C for y, to get

So the slope of Ax 6+ By = C is This fact can be used in checking standard form. The slope of 2x - 4y = 3 in Example 2 is , which is the slope of the original equation.

 
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